16/(x^2-7x+10)=-4x/(x-2)

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Solution for 16/(x^2-7x+10)=-4x/(x-2) equation:


D( x )

x-2 = 0

x^2-(7*x)+10 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x^2-(7*x)+10 = 0

x^2-(7*x)+10 = 0

x^2-7*x+10 = 0

x^2-7*x+10 = 0

DELTA = (-7)^2-(1*4*10)

DELTA = 9

DELTA > 0

x = (9^(1/2)+7)/(1*2) or x = (7-9^(1/2))/(1*2)

x = 5 or x = 2

x in (-oo:2) U (2:5) U (5:+oo)

16/(x^2-(7*x)+10) = (-4*x)/(x-2) // - (-4*x)/(x-2)

16/(x^2-(7*x)+10)-((-4*x)/(x-2)) = 0

16/(x^2-7*x+10)+4*x*(x-2)^-1 = 0

16/(x^2-7*x+10)+(4*x)/(x-2) = 0

x^2-7*x+10 = 0

x^2-7*x+10 = 0

x^2-7*x+10 = 0

DELTA = (-7)^2-(1*4*10)

DELTA = 9

DELTA > 0

x = (9^(1/2)+7)/(1*2) or x = (7-9^(1/2))/(1*2)

x = 5 or x = 2

(x-2)*(x-5) = 0

16/((x-2)*(x-5))+(4*x)/(x-2) = 0

16/((x-2)*(x-5))+(4*x*(x-5))/((x-2)*(x-5)) = 0

4*x*(x-5)+16 = 0

4*x^2-20*x+16 = 0

4*x^2-20*x+16 = 0

4*(x^2-5*x+4) = 0

x^2-5*x+4 = 0

DELTA = (-5)^2-(1*4*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+5)/(1*2) or x = (5-9^(1/2))/(1*2)

x = 4 or x = 1

4*(x-1)*(x-4) = 0

(4*(x-1)*(x-4))/((x-2)*(x-5)) = 0

(4*(x-1)*(x-4))/((x-2)*(x-5)) = 0 // * (x-2)*(x-5)

4*(x-1)*(x-4) = 0

( x-1 )

x-1 = 0 // + 1

x = 1

( x-4 )

x-4 = 0 // + 4

x = 4

x in { 1, 4 }

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